Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The minimum speed divided by 10 in m/s with which a projectile must be thrown from origin at ground so that it is able to pass through a point P (30 m, 40 m) is :(g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
3
Ans. 3
Sol. As y = x tan θ – 
(1 + tan 2 θ )
for (a, b), ga 2 tan 2 θ – 2au 2 tan θ + (ga 2 + 2bu 2 ) = 0
as discriminant must be positive
4 a 2 u 2 – 4ga 2 (ga 2 + 2bu 2 ) ≥ 0
Solving,
u ≥ 
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